Time Period Of A Satellite Of Mass M Revolving Around Very Close To Earth

A satellite of mass m is revolving close to the surface of a planet of density d with time period t what is the value of universal gravitational constant 6537268.

Time period of a satellite of mass m revolving around very close to earth.

A satellite of mass is orbiting the earth in a cicular orbit of radius it starts losing its mechanical energy due to small air resistance at the rate of joule sec. T 5071 3600 1 408 h. Acceleration due to earth at a point near to earth g g m r. The speed of the satellite in its orbit is.

Radius of earth r 6400 km 6 4 x 10 8 m radius of orbit of moon r 3 84 x 10 5. From the following data calculate the period of revolution of the moon around the earth. Distance of moon from the earth 3 84 x 10 5 km. If the density of moon is d the time period of revolution of an artificial satellite in a circular orbit very close to the surface of the moon is.

Radius of earth 6400 km. The mean angular velocity of the earth around the sun is 1 per day. The period of the earth as it travels around the sun is one year. This velocity is called the orbital velocity of the satellite.

View answer a satellite close to the earth is in orbit above the equator with a period of revolution of 1. Let the mass of earth be m. A satellite keeps on revolving round the earth with a certain velocity which depends on the radius of its orbit. 5 h o u r s in the same sense as that of the earth.

Let v 0 be the orbital velocity of the satellite. You can calculate the speed of a satellite around an object using the equation. T 2πr v c 2 x 3 142 x 6400 7 931 5071 s. For synchronisation its period of revolution around the earth must be equal to the period of rotation of the earth ie 1 day 24 hr 86400 seconds.

Let the radius of earth be r. The time period of a satellite orbiting around the earth is given by. Consider a satellite of mass m moving in a circular orbit around the earth at a distance r from the centre of the earth. Suppose a satellite of mass m revolving around the earth at height h form the surface as shown in the figure.

If you know the satellite s speed and the radius at which it orbits you can figure out its period. Centripetal acceleration v r. As the movement of satellites is uniform circular motion so there will be only centripetal acceleration. The speed of the satellite is 7 519 km s and the period of revolution of the satellite is 5930 s.

G 9 8 m s 2. The time taken by the satellite to hit the suface of the earth is and are the mass and radius of the earth.